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A Repeatable Setup System for Chain Rule Problems

1Naming the Layers Before Differentiating2Writing the Derivative as a Labeled Product3Running the Layout on the Standard Function Families4Keeping the Layout Intact Inside Products and Quotients5Extending the Layout to Implicit Differentiation and Diagnosing Setup Errors
Extending the Layout to Implicit Differentiation and Diagnosing Setup Errors

Locating the Broken Step in a Wrong Chain Rule Solution

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Here is a solution that looks reasonable and is wrong: the derivative of sine of x squared written as just cosine of x squared. The layout tells you where it broke.
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The setup

Suppose a solution claims

\[\frac{d}{dx}\left[\sin\left(x^2\right)\right]=\cos\left(x^2\right)\]

This is a plausible-looking answer, and it is wrong. The layout tells you exactly where it broke.

Step 1: layer count

The expression \(\sin(x^2)\) has two layers:

  • outer: \(\sin(;)\)
  • inner: \(x^2\)

Two layers means two factors. The claimed answer has one factor, \(\cos(x^2)\). The layer count and the factor count disagree, so the solution is already flagged.

Step 2: factor count

Write the block properly:

\[\frac{d}{dx}\left[\sin\left(x^2\right)\right]=\cos\left(x^2\right)\cdot 2x\]

The correct answer has two factors. The wrong answer is missing the innermost layer derivative, \(2x\).

Step 3: inner-function preservation

Check that the inner expression was copied unchanged into the outer derivative factor. Here \(\cos(x^2)\) does keep \(x^2\) intact, so this check passes. The error is not a drifted argument; it is a dropped factor.

A second failure mode

Compare with

\[\frac{d}{dx}\left[\ln\left(x^2\right)\right]=\frac{1}{x}\cdot 2x=2\]

Here the factor count is right and the innermost derivative is right, but the outer derivative was evaluated at \(x\) instead of at the inner function. The correct block is

\[\frac{d}{dx}\left[\ln\left(x^2\right)\right]=\frac{1}{x^2}\cdot 2x=\frac{2}{x}\]

The inner-function-preservation check is the one that catches this, and it is the only check that catches it.

Why three checks

Each check targets a different failure mode:

Check Failure it catches
Layer count Wrong number of factors expected
Factor count A dropped or duplicated factor
Inner-function preservation Outer derivative evaluated at the wrong argument

Running them in this order means the first failing check names the broken step.

References

  1. [1]Chain Rule | Varsity Tutorsvarsitytutors.com
  2. [2]Chain Rule Explained — Step-by-Step with Examples | CalculusConcepts.comcalculusconcepts.com
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