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A Repeatable Setup System for Chain Rule Problems

1Naming the Layers Before Differentiating2Writing the Derivative as a Labeled Product3Running the Layout on the Standard Function Families4Keeping the Layout Intact Inside Products and Quotients5Extending the Layout to Implicit Differentiation and Diagnosing Setup Errors
Running the Layout on the Standard Function Families

Chain Rule on Sine and Cosine Composites

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The power composite worked, so push the same two slots onto a trig composite. In sine of four x, the outer layer is sine and the inner layer is four x. The outer slot gets cosine with the inside copied unchanged, so cosine of four x, not cosine of x.
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The layout on trigonometric composites

Trig composites follow the same two-slot procedure. Only the outer derivative changes.

Example 1: \(\sin(4x)\)

  • Outer layer: \(\sin(\square)\), whose derivative is \(\cos(\square)\).
  • Inner layer: \(4x\), whose derivative is \(4\).

\[\frac{d}{dx}\sin(4x) = \cos(4x) \cdot 4\]

The argument of the cosine is \(4x\), not \(x\). Writing \(\cos(x)\cdot 4\) breaks the rule that the outer factor is evaluated at the inner function.

Example 2: \(\cos(x^3)\)

  • Outer layer: \(\cos(\square)\), whose derivative is \(-\sin(\square)\).
  • Inner layer: \(x^3\), whose derivative is \(3x^2\).

\[\frac{d}{dx}\cos(x^3) = -\sin(x^3) \cdot 3x^2\]

Two things to watch. First, the minus sign belongs to the outer factor, so it appears before the sine. Second, the inner factor is \(3x^2\), not \(3x\) and not \(2x\).

The pattern

Composite Outer factor Inner factor
\(\sin(4x)\) \(\cos(4x)\) \(4\)
\(\cos(x^3)\) \(-\sin(x^3)\) \(3x^2\)

In both rows the outer factor keeps the inner expression intact inside the trig function, and the inner factor is written separately at the end.

References

  1. [1]Chain Rule: Practice Problems & Solutionsmatheno.com
  2. [2]Chain Rule | Varsity Tutors AP Calculusvarsitytutors.com
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