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A Repeatable Setup System for Chain Rule Problems

1Naming the Layers Before Differentiating2Writing the Derivative as a Labeled Product3Running the Layout on the Standard Function Families4Keeping the Layout Intact Inside Products and Quotients5Extending the Layout to Implicit Differentiation and Diagnosing Setup Errors
Writing the Derivative as a Labeled Product

Building a Three-Layer Product Without Dropping a Layer

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Now a three-layer problem: e to the sine of three x. Three layers means three slots, and you fill them from the outside in. The exponential is outermost, so its derivative is itself, with the sine of three x still sitting in the exponent.
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Take \(y=e^{\sin(3x)}\). The layer inventory from the previous chapter gives three layers, so the derivative must have three factors.

Layer inventory.

  • Outermost: \(e^{\square}\)
  • Middle: \(\sin(\square)\)
  • Innermost: \(3x\)

Fill the factors in order, outside in.

  1. Derivative of \(e^{\square}\) at the middle layer: \(e^{\sin(3x)}\)
  2. Derivative of \(\sin(\square)\) at the innermost layer: \(\cos(3x)\)
  3. Derivative of \(3x\): \(3\)

Full product.

\[\frac{dy}{dx}=e^{\sin(3x)}\cdot\cos(3x)\cdot 3\]

The factor-count check. Count the factors you wrote: three. Count the layers you inventoried: three. They match, so no layer was skipped. If you had written only \(e^{\sin(3x)}\cos(3x)\), the count would be two against three layers, and the missing factor would be immediately visible.

Where the dropped layer usually hides. In a three-layer composite the middle factor is the one most often lost, because it is neither the obvious outer function nor the final linear piece. The count check catches it without requiring you to re-derive anything.

References

  1. [1]Chain rule – Wikipediaen.wikipedia.org
  2. [2]Chain Rule: Practice Problems & Solutionsmatheno.com
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